12p^2-25pq-7q^2=0

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Solution for 12p^2-25pq-7q^2=0 equation: 


Simplifying
12p2 + -25pq + -7q2 = 0

Reorder the terms:
-25pq + 12p2 + -7q2 = 0

Solving
-25pq + 12p2 + -7q2 = 0

Solving for variable 'p'.

Factor a trinomial.
(3p + -7q)(4p + q) = 0


Subproblem 1
Set the factor '(3p + -7q)' equal to zero and attempt to solve:

Simplifying
3p + -7q = 0

Solving
3p + -7q = 0

Move all terms containing p to the left, all other terms to the right.

Add '7q' to each side of the equation.
3p + -7q + 7q = 0 + 7q

Combine like terms: -7q + 7q = 0
3p + 0 = 0 + 7q
3p = 0 + 7q
Remove the zero:
3p = 7q

Divide each side by '3'.
p = 2.333333333q

Simplifying
p = 2.333333333q

Subproblem 2
Set the factor '(4p + q)' equal to zero and attempt to solve:

Simplifying
4p + q = 0

Solving
4p + q = 0

Move all terms containing p to the left, all other terms to the right.

Add '-1q' to each side of the equation.
4p + q + -1q = 0 + -1q

Combine like terms: q + -1q = 0
4p + 0 = 0 + -1q
4p = 0 + -1q
Remove the zero:
4p = -1q

Divide each side by '4'.
p = -0.25q

Simplifying
p = -0.25q
Solution
p = {2.333333333q, -0.25q}

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